**SUMMARY: Our Sun slices FEATURES in an E-W orientation, along Latitude lines! This is ORTHOGONAL to the ARCUATE SHEAR for the other Solar system MASSES, and the appropriate EQUATION is:**__investigated,__

**(90- X)/X= degrees**

**e.g. for 7.2, the SOLUTION is 9.97560976 degrees from the REFERENCE Mendocino. Checking this calculation: (90-10.97560976)/10.97560976= 7.2. (**

**APPROPRIATE EQUATION is (90-8.2)/8.2= 9.97560976W, for Latitude LOCATION).**

**Don't forget the UNIT in the calculations, to solve for X= 10.97560976. This relation is DEPENDENT upon the 800km (7.2d x 111.11111km per degree Latitude= 800 km) LINEARS, such as is shown by the Sierras, or the 2400 km for Atlas Mtns.**

**The EFFECTS of the Sun and Moon are PERPENDICULAR to each other, i.e. the Sun shears at RIGHT ANGLES to the Moon!**

__,__

**The Sun's Latitude, AXIAL TILT EQUATION: (90- X)/X= INDEX, with the Equinoxial - Sun's TILTS**

**yields: (90- 17.233)/17.233= 4.22538, and checking: (90- 5.22538)/5.22538= 16.233 (don't forget the unit 1, which is also the DIFFERENCE between 14.18 degrees/day for the Sun's rotation daily and the Earth's MOON at 13.18). The DEFICIT for this latitude is 40.35816945- 16.233= 24.12517 degrees. The ratio of 40.43847N Latitude/23.43741N = 1.7, for the combination of Tropic of Cancer and 7.2d. This can be viewed via the below DIAGRAM, where the Sun's 7.2 Axial TILT contrasts with Earth's 23.433 degree tilt (+ 16.233 degrees for the ORBITAL difference= 39.666, the action creating the 7.2 Latitude Mendocino. CA TRANSFORMS' separation, 88 km error):**

**For the North Pacific Ocean, TRANSFORM are exhibited to just BELOW the EQUATOR:**

**7.2 Latitude degrees= 800km, in a N-S direction; this is shown for a DIAGONAL, and the 800 MULTIPLES occur for the ENTIRE GLOBE: Atlas, Chilean ANDES, Owen Stanley, and Sierras LINEAR MOUNTAINS:***,*

**The Sun scribes TRANSFORMS and shear features E-W, perpendicular to the other Solar MASSES**__which__

**.**

__for the Moon is N-S with a SINK, "hole", BASIN or Lake-Sea along the PATH__

*I tried to find Meridians which would fit the EQUATION:*

*(360 degrees- a Meridian in degrees, related to the Prime)/M, which is equal to the Inclination of the Orbital Plane, I, but the Sun does NOT FIT this orientation!*

__Instead, the sun travels south to north during a year, and then returns- fixing the Tropics of Cancer and Capricorn. This TRAVEL is approximately 23.433 twice yearly= 46.866 degrees corrected for the PRECESSION of the Equinox (46 + degrees). This is a FRACTION of the 360 degree CIRCLE, and the division (90- 47.866)/47.866= .8802__

**For Other Solar MASSES, (360- 7.62711864)/7.62711864= 46.2d, the Longitudinal DIFFERENCE between the Natural Prime meridian, at 169.6W longitude in the Greenwich System= 123.4 degrees or 123.4W longitude, which is near the CA region at 40N Latitude. This does NOT FIT the Sun, but it yields a Meridian useful to view the EXTENDING province versus the SHRINKING Pacific Ocean (123W longitude):**

**The ANGLE thought to be 45 degrees, because of the CA-NV diagonal boundary, conforms to Eris ASTEROID with a 44.19d INCLINATION from the Ecliptic! This asteroid is about the SIZE of Pluto, but is MUCH CLOSER to earth, so is more FORCEFUL in creating the 800 km PATTERN. Much MORE DIFFICULT will be the ANALYSIS of Owen Stanley Range and Atlas Mountains, because of the GREATER AGE- allowing an EXPANSION NW-ward over the INTERVENING years!**

__The 800 km LINEAR should be traced from the JUT of Mendocino to the Santa Barbara Channel, below:__

**REVERSE VIEW of Island at 800 km:****A clue to the CONTINUATION of the 800km LINEAR, even though it is NOT ORIENTED N-S, is the arrangement of LINEAR 800**

__multiples__Mountain RANGES around the Globe. An EXAMPLE is the Atlas Mountains (2400 km), N. Africa ( it bows in the mid-section, since the Continent is moving NW-erly at that location):

**The Chilean ANDES are oriented N-S, and exhibit the LONGEST RANGE of 3200 km:**

Where does this leave us? The SUN has CHANGED its AXIAL TILT PERIODICALLY, leaving it near 7.2 degrees at present. Previously (since 41 m.y. ago), it has deviations from this TILT, as shown by the following:

**Below CALCULATION yields 7.4231d AXIAL TILT, and each MAJOR TRANSFORM should be evaluated:****Above is the set of N-S LINEARS, which will be used to find the appropriate INSTIGATOR, from the EQUATION; (360-x)/x= longitude from Prime NATURAL Meridian. Using 158.1773, x = 10.25, or 7 degrees for Mercury's INCLINATION + 1= 8, checking (90- 8)/8= 10.25, and (90-11.25)/11.25= 7.**

__CHECKS, and this is a Mercury Meridian N-S LINEAR, at 158.1773W or 158 10'38.28"W__

**Above has a 2.4% VARIATION from the Literature's 7.25d TILT, and this will be COMPARED to other MAJOR TRANSFORMS:**

__Above is the exhibit of the Sun's WOBBLE, and below is the LARGE VIEW to the CENTRAL AMERICA anomaly:__

**These are proceeding to the 6th CYCLE, in the South Pacific:**

**Why are the Sun Line TRANSFORMS mostly in the Northern Pacific? Further, why are there FEW in the Atlantic Ocean which CONFORM to the 7.2 degrees separation?**

**Transforms trace E-W exist from the 40.4N (more PRECISE: 40.438469N) Latitude at Mendocino, CA to just below the Equator, and extend the 2 x 23.4333= 46.8666 degrees of the Tropic of Cancer to Capricorn (SPREAD). This would be at 6.6666S latitude:**

**Pacific SW Transform:**
DETAILED VIEW:

**Above Transform lies at 10S Latitude, and**

__should NOT be INCLUDED__. This is in the ZONE of RISING ISLANDS, which belong to the Northerly-moving Australia BLOCK of Crust! A better transform to evaluate is that further north, at__the 5.2S Latitude:__

__The most south TRANSFORM in this set is: 36.866/7.2= 5.12 degrees (shown above).__

__Comparing the Pacific with the Atlantic TRANSFORMS:__

__MAR Transform separations (small error)__

*The Atlantic Ocean is EXPANDING E-W, and this is a MAJOR DIFFERENCE with the Pacific- which is CONTRACTING! The Pacific has a MAL-DISTRIBUTION of transforms- NOT CENTERED near the Tropic of Cancer to Capricorn (Equator), and which are YOUNGER to the North.*

**The Sierras- which are less than 50 m.y. AGE- are 800km in extent (7.2d, when oriented N-S), and EXHIBIT many E-W segments along the 40N latitude line. The ONLY linear Range in the Southern Hemisphere (3200km length and OLDER) is that of the Andes, compared to Atlas (2400km), Owen Stanley 1600km at (Equator), and Sierras.**

**GRAPH IT!**

__With a FEW EXCEPTIONS, the trend of the TILT is LINEAR! The__*Sun's AXIAL TILT, like EARTH, is WOBBLING, and changing its ANGLE regularly*__. This makes for a TUMULTUOUS FUTURE, since the cycles are SIMILAR to the comparison between the Colorado Plateau AXIAL and the Basin and Range PRECESSION, with a SHARP DIVIDE (Hf, or Hurricane Fault) between the two (which is moving with the Earth PRECESSING, TILTING and WOBBLING)!__

**DOUBLE ANOMALY at 39W and Mendocino TRANSFORM:**

Above 39N transform EXHIBITS a N-S anomaly, since it occurs at an INTERSECTION with a feature that is 23E of Prime (23.436444E).

**Inspect the ANOMALY:**

**The CROSS FRACTURES bear further ANALYSIS:**

**BELOW is our PRIMARY LAND REFERENCE (JUT of Mendocino):**

**Above and BELOW shows that the sun LINE and Moon line are both CREATING ORTHOGONAL SLICES on the transform exhibit. We next must FIND how to CONFIRM the 2x RELATION between Moon and Sun (20.48= 2x 10.24 for the Sun's TIDAL EFFECT).**

*We are trying to determine why the Tropic of CANCER to Capricorn 46.8666 degree EXTENT exhibits a TRACE from the Mendocino 40.2 Latitude to a TRANSFORM 4.6666S of the Equator; this is NOT CENTERED on the ZERO LATITUDE!*

EXPANDING:

**VIEWING the farthest SOUTH LATITUDE, where SIGNIFICANT TRANSFORMS occur (but not in blocks farther south):**

*Note that I have used TRIAL AND ERROR to find the line of SEAMOUNTS which would FIT the 47.8666d extent. This is EXHIBITED near the LINE ISLANDS, and I then RE-PLOTTED, RE-CALCULATED. NW Corner:*

__NOT KNOWING the Tropics EXHIBIT, you would suspect that a Meteor strike occurred (which I had previously suspected)! Now it is CLEAR that this represents an INSTABILITY of the Earth's CRUST, PROBABLY more accurately at 18.83846945N or 7.2 x 3 cycles= -21.6+ 40.43846945 Mendocino Latitude, 170.6W. WORKING BACKWARDS, the calculated Sun TILT ANGLE is 47.8666- 40.2= 7.6666 degrees. I'll RE-CHECK this using other MEASUREMENTS!__

__Pacific HOLE (created by MOON TIDES), south CORNER:__

__Above is the MORE ACCURATE south corner, at the most SOUTHERLY EXTENT of the Tropics INFLUENCE (created by SUN TIDES). Below is the expanded VIEW:__

__SIGNIFICANT ANOMALIES occur along this N-S sun LINE:__

**ANOMALIES along the Tropic of Cancer LINE, Hawaii above, and Aleutian CHAIN below:**

**Since the Moon Equation does NOT APPLY, test the ORTHOGONAL:**

**(90- X)/X= degrees on PROTRUSIONS- which exhibit 800 MULTIPLES from KNOWN ANOMALIES, e.g. the Florida TIT developed after the 256 m.y. Appalachian EVENT:**

**I'll re-record the ABOVE!**

**The 800km LINEAR is 17 degrees from N-S: PLUTO'S Inclination to the ECLIPTIC PLANE!**

**25N 80W, 90E of Prime:**

*AMAZINGLY, the TIT exhibits a NIPPLE, after I had named this feature last year!*

**The AMAZON tit has developed from the SA orb, from the 3200 km LINEAR pf the Chilean ANDES.**

__The deviation of the Range from N-S, at 7 degrees, PERTAINS to the 7 degree ORBITAL INCLINATION of MERCURY!__

*Mercury AUGMENTS the Sun!*

**3200 km LINEAR in the southern HEMISPHERE:****CHECK, for yourself, whether the Atlas and Owen Stanley 800 MULTIPLES Ranges fit this ANALYSIS (YOU may have to use Eris at 44.19d, and Ceres ASTEROID at 10.58d for these!).**

**Above is an ANOMALY found by using the EQUATION: (90- 8.2d)/8.2=9.97560396, or 30.22439N. This is at a CRITICAL LONGITUDE, so exhibits both Sun and MOON influence!**

__, and the appropriate__

**SUMMARY: Our Sun scribes FEATURES in an E-W orientation! This is ORTHOGONAL to the ARCUATE SHEAR for the other Solar system MASSES (excepting ones creating DIAGONALS- such as Venus and those with large Inclination ANGLES)**

**EQUATION is:**

**(90- X)/X= degrees investigated, e.g. for 7.2, the SOLUTION is 9.97560976 degrees from the REFERENCE Mendocino. Checking this calculation: (90-10.97560976)/10.97560976= 7.2. Don't forget the UNIT in the calculations, since (90-X)= X(7.2), or 8.2X= 90, or X= 10.97560976. This relation is DEPENDANT upon the 800km (7.2d x 111.11111km per degree Latitude= 800km) RECURRING FEATURE!**

__NOTE: The Prime NATURAL Meridian lies between the 2 Diomede Islands, BETWEEN 169.6W and 169d 40'W__, a DIFFERENCE of .0666 degrees (4 minutes of Longitude, or 1/15th). The Meridian may be made MORE PRECISE, by referring to other CRITICAL COORDINATES, in locations such as Greenland- where the Moon LINE dividing the Island at 44W longitude yields a RATIO of 2.0 at 46.754W, AFTER a CORRECTION for the CRITICAL COORDINATES for Mars. This was indicated by the ratio 1.88- which is the Mars/Earth year ratio.

**This, in the EQUATION: (360-2.88)/2.88 = 124 degrees from the location at 45W, yields a CORRECTED Prime NATURAL Meridian of 169W longitude, relative to Greenwich. Remember that the Greenwich Meridian is ARBITRARY, while the Diomede Islands Meridian is a NATURAL DIVISION of the Earth's Crust, where the two CONTINENTS are approaching!**

*The CALIBRATION may be further compared, by using the SINK at Hudson Bay. This location has CRITICAL COORDINATES of 60N 80W- which is 90 degrees from Diomede Islands, APPROXIMATELY. The comparison will make this more accurate!*

*Hudson Bay 2.0 RATIO:*

**There is a 12 km ERROR (1.2%)!**

**Since the ANALYSIS-CALCULATIONS yield 170W as the CORRECTED PRIME MERIDIAN, look at this Meridian between Alaska and DIOMEDES:**

__Until I find BETTER CONFIRMATION, use the 170W Meridian for the NATURAL PRIME MERIDIAN; it is SIMPLER (BUT 169.6W is more CORRECT)! 170W appears SUSPICIOUS, since it "ROUNDS OFF" what is an ARBITRARY SYSTEM in the Greenwich REFERENCE.__

*I have solved this by TRIAL and ERROR, with the CRITICAL COORDINATES used as GUIDES. This entails ENLARGING the Photo as much as possible, and finding the coordinates fitting the BINARY THEOREM. These are somewhat in error, and the location is also, so that the COMBINATION of Coastline, Coordinates, and WIDEST or LONGEST EXTENT becomes apparent!*

__The Sun's Latitude, AXIAL TILT EQUATION: (90- X)/X= INDEX, with the Equinoxial - Sun's TILTS, yields: (90- 17.233)/17.233= 4.22538, and checking: (90- 5.22538)/5.22538= 16.233 (don't forget the unit 1, which is also the DIFFERENCE between 14.18 degrees/day for the Sun's rotation daily and the Earth's 13.18). The DEFICIT for this latitude is 40.35816945- 16.233= 24.12517 degrees. The ratio of 40.43847N Latitude/23.43741N = 1.7, for the combination of Tropic of Cancer and 7.2d. This can be viewed via the below DIAGRAM, where the Sun's 7.2 Axial TILT contrasts with Earth's 23.433 degree tilt (+ 16.233 degrees for the ORBITAL difference= 39.666, the action creating the 7.2 Latitude Mendocino. CA TRANSFORMS' separation):__

*There is still a SMALL ERROR: 40.4384- 39.666= .80 degrees, and this may relate to the 90 km since the last TRANSFORM MOVEMENT. I'll CROSS-CHECK!*

**A major DIFFICULTY is the determination whether the EXTENT, E-W- of the transform- indicates the TIME INTERVAL of the ON-GOING EVENT!**

**Below is a START by viewing a MINING AREA: Goldstrike:**

**ANALEMMA may be used to determine TIME INTERVAL, which could be AGE, for YOUNG FEATURES!**

**To be CONTINUED!**